Armed with a continuous blue line, as described in the previous post (but see also this later post), we can write this more compactly as a single lead:
12345678
21436587
12346857
21438675
24136857
42316587
24135678
42315768
24351786
23457168
32541786
35247168
53427618
35246781
32547618
23456781
24365871
42638517
46235871
64328517
46238157
42631875
24368157
23461875
32416857
23146587
32415678
23145768
21347586
12435768
21345678
12436587
14263857
We can also write out what happens when “bob” is called. The front two bells are unaffected, and run in and out as in a plain course to become the 2nd and 3rd place bells. The bell in 4th place, which would have run out to 5th and become the 5th place bell, instead makes the 4th-place bob and becomes the 4th place bell. The bells above 4th place each dodge back one place, which brings them back to their starting positions, so that they simply repeat the same lead as they have just done. Like this:
23145768
21347586
12435768
21345678 bob
12436587
14235678
The bob permutes the 2nd, 3rd and 4th place bells. If called at the end of each of the first three leads this will bring the touch back to rounds – three leads of Bristol.
Thank you. Perfectly clear at last, from an older ringer who asks for Bristol 8 and cops 3 blasted bobs when all I wanted was a plain course, just for once, which makes it clear for me.
Hello Simon, just reading your comments on Bristol major where you state two and three are unaffected, but if they run in and out respectively, then they are affected, are they not?
No, they aren’t affected, becuase they do the same thing as when there isn’t a bob. The bell that has dodged 1–2 up with the treble still goes out to become the 3rd-place bell. And the bell that has dodged 3–4 down still goes in to become the 2nd-place bell.
If you look at the bottom line of the grid with and without a bob you will see that the 4 and the 2 are in the same place in both grids, i.e., they are unaffected.
I can ring Bristol but I simply don’t understand any of the calls ‚is affected bells and what they do
All the other standards 8 methods are simple.
I want to learn it so I can ring 8 spliced
The bell dodging 3–4 up, which would have gone out to 5th place, instead makes 4ths place, becoming the 4th place bell, dodging 3–4 down before passing the treble.
The bell dodging 1–2 up with the treble goes out to 3rd place, becoming the 3rd – just as it would have done if no bob had been called.
The bell dodging 3–4 down goes down to 2nd place, becoming the 2nd and dodging 1–2 down with the treble – just as it would have done if no bob had been called.
The bells above 4th place all dodge at the next backstroke, which brings them back to where they were at the start of the lead, so they repeat the same work for the followng lead – i.e. the 5th place bell becomes the 5th, the 6th becomes the 6th, the 7th becomes the 7th and the 8th becomes the 8th.